Now from eq.2 we have 1/2(x+y) = 1/3(x-y) or 3x-3y = 2x+2y or 3x-2x = 3y+2y or x = 5y..... .....eq.(3)
Putting value of x in eq. (1) we have 6/(5y+y) = 7/(5y-y) +3 or 6/6y = 7/4y +3 or 1/y = (7+12y)/4y or 12y.y + 7y = 4y (by cross multiplication) or 12y.y. + 3y = 0 or 3y(4y+1) =0 or 4y+1 = 0 or y= -1/4