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Byju's Answer
Standard X
Mathematics
Fundamental Theorem of Arithmetic
Solve fol 1/2...
Question
Solve for x :
1
2
x
−
3
+
1
x
−
5
=
1
1
9
,
x
≠
3
2
,
5
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Solution
Given,
1
2
x
−
3
+
1
x
−
5
=
1
1
9
x
−
5
+
2
x
−
3
(
2
x
−
3
)
(
x
−
5
)
=
10
9
3
x
−
8
2
x
2
−
13
x
+
15
=
10
9
9
(
3
x
−
8
)
=
10
(
2
x
2
−
13
x
+
15
)
27
x
−
72
=
20
x
2
−
130
x
+
150
20
x
2
−
157
x
+
222
=
0
20
x
2
−
120
x
−
37
x
+
222
=
0
20
x
(
x
−
6
)
−
37
(
x
−
6
)
=
0
(
x
−
6
)
(
20
x
−
37
)
=
0
Either x - 6 = 0 or 20x - 37 = 0
⇒
x
=
6
,
x
=
37
20
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107
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