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Byju's Answer
Standard IX
Mathematics
Zeroes of a Polynomial
Solve for x x...
Question
Solve for x
x
2
−
(
1
+
√
5
)
x
+
√
5
=
0
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Solution
x
2
−
(
1
+
√
5
)
x
+
√
5
=
0
x
2
−
x
−
√
5
x
+
√
5
=
0
x
(
x
−
1
)
−
√
5
(
x
−
1
)
(
x
−
√
5
)
(
x
−
1
)
x
=
√
5
o
r
x
=
1
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