Solve for x x-2- 5x-8 3

x 2≤ 5x+8 3 = gt;3x 6≤ 5x+8 = gt;5x 3x≥ 6 8 = gt;2x≥ 14 = gt;x≥ 7 ...

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Solve for x...

Question

Solve for $x$
$x - 2 \leq \frac{5 x + 8}{3}$

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Solution

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x

(5 x + 1) (x + 3) - 8

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Simplify : $\frac{x^{2} - 5 x - 24}{(x + 3) (x + 8)} \times \frac{x^{2} - 64}{{(x - 8)}^{2}}$

x^{2} - 5 x + 6 = x^{2} + 5 x - 8

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