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Question
Solve:
15(2−y)−5(y+6)1−3y=10
15(2−y)−5(y+6)1−3y=10
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Solution
15(2−y)−5(y+6)=10(1−3y)30−15y−5y−30=10−30y−15y−5y+30y=10−30+3010y=10∴y=1
15(2−y)−5(y+6)=10(1−3y)30−15y−5y−30=10−30y−15y−5y+30y=10−30+3010y=10∴y=1
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