Solve - 152-y-5y-6-1-3y-10

15(2 y) 5(y+6)/1 3y=10 By cross multiplication, 15(2 y) 5(y+6)=10(1 3y) ⇒ 30 15y 5y 30=10 30y ⇒ 15y 5y+30y=10 30+30 ⇒ 30y 20y=10⇒ 10y=10 ⇒ y=10/10=1 Hence y = ...

279

You visited us 279 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

Solve : 152-y...

Question

Solve :

$\frac{15 (2 - y) - 5 (y + 6)}{1 - 3 y} = 10$

Open in App

Solution

$\frac{15 (2 - y) - 5 (y + 6)}{1 - 3 y} = 10$

By cross multiplication,

$15 (2 - y) - 5 (y + 6) = 10 (1 - 3 y) \Rightarrow 30 - 15 y - 5 y - 30 = 10 - 30 y \Rightarrow - 15 y - 5 y + 30 y = 10 - 30 + 30 \Rightarrow 30 y - 20 y = 10 \Rightarrow 10 y = 10 \Rightarrow y = \frac{10}{10} = 1 Hence y = 1 Ans.$

Suggest Corrections

Similar questions

Solve for x and y:

$6 x + 5 y = 7 x + 3 y + 1 = 2 (x + 6 y - 1)$

Q. Solve it

3 x + 3 y = 1 (i)

3 x + 5 y = 2 (i i)

x = ? y = ?

Q. Solve for y: 3y = 5y - 8/3

Solve for x and y:

$3 x - 5 y - 19 = 0, - 7 x + 3 y + 1 = 0.$

Q. Solve:

3 (y - 7) - 2 (3 y - 4) = (2 - 5 y)

Join BYJU'S Learning Program

Solve : 15(2−y)−5(y+6)1−3y=10

15(2−y)−5(y+6)1−3y=10 By cross multiplication, 15(2−y)−5(y+6)=10(1−3y)⇒ 30−15y−5y−30=10−30y⇒ −15y−5y+30y=10−30+30⇒ 30y−20y=10⇒ 10y=10⇒ y=1010=1Hence y = 1 Ans.

Solve :

$\frac{15 (2 - y) - 5 (y + 6)}{1 - 3 y} = 10$