Question

Solve: $\frac{2}{3}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{3}{4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{2}$

• A. $\frac{9}{6}$
• B. $\frac{12}{23}$
• C. $\frac{6}{9}$
• D. $\frac{23}{12}$

Answer 1

The correct option is D $\frac{23}{12}$

$\frac{2}{3}$ + $\frac{3}{4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{2}$
LCM of 3, 4 and 2 = 12

$\frac{2\times 4}{3\times 4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{3\times 3}{4\times 3}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1\times 6}{2\times 6}$

= $\frac{8}{12}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{9}{12}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{6}{12}$

= $\frac{8+9+6}{12}$

= $\frac{23}{12}$