Question

Solve : $\frac{2x+3}{5}>\frac{4x-1}{2},xϵW.$

Answer 1

$\frac{2x+3}{5}>\frac{4x-1}{2},xϵW.$

$\Rightarrow 2(2x+3)>5(4x-1)$

$\Rightarrow 4x+6>20x-5$

$\Rightarrow 4x-20x>-5-6$

$\Rightarrow -16x>-11$

$\Rightarrow x<\frac{-11}{-16}(Dividingby-16)$

$\Rightarrow x<\frac{11}{16}$

$\Rightarrow x<\frac{11}{16}$

$\therefore$ x = 0

$\therefore$ Solution set = {0}