Question

Solve graphically.

Express answers in both inequality and interval notation.

$\frac{x+4}{1-x}\le 0$

Answer 1

$\frac{x+4}{1-x}\le o$

$\frac{x-(-4)}{-(x-1)}\le o$

$g\left(x\right)=\frac{x-(-4)}{x-1}\le$

critical points

$x-(-4)=0$ $x-1=0$

$x=-4$ $x=1$

$g\left(n\right)+ve$ in $xϵ(-\infty ,-4]\cup (1,\infty )$

$\therefore$ domain $xϵ(-\infty ,-4]\cup (1,\infty )$