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Question

Solve graphically the following pair of linear equations:

2x+3y12=0,2xy4=0.

A
x=0,y=1
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B
x=4,y=3
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C
x=3,y=2
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D
x=0,y=5
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Solution

The correct option is A x=3,y=2
2x+3y12=0
2x=123y
x=123y2
Let, y=2, then x=123(2)2=3
Similarly, when y=0,x=6
2xy4=0
2x=4+y
x=4+y2
Let, y=2, then x=4+22=3
Similarly, when y=0,x=2
Plotting the points above, the intersecting point is (3,2)
x=3,y=2

798116_232436_ans_b0e02cbf7b04417db716b52e98653051.png

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