Question

Solve
$\int \frac{x^2-1}{(x+1)}dx$.

Answer 1

$I=\int \frac{x^2-1}{x+1}dx$

$I=\int \frac{(x+1)(x-1)}{x+1}dx$

$I=\int (x-1)dx$

$I=\frac{x^2}{2}-x+C$