wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve dx5x22x

A
I=15logx15155x22x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
I=15logx15+155x22x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
I=15logx15+155x22x+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B I=15logx15+155x22x+c
dx5x22x

=15dxx225x

=15dxx225x+125125

=15dx(x15)2(15)2

=15logx15+x225x+c

=15logx15+155x22x+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon