Question

Solve $\int \sin 2x\cos 2xdx$.

Answer 1

$\int \sin 2x\cos 2xdx$.

$=\frac{1}{2}\int 2\sin 2x\cos 2xdx$

$=\frac{1}{2}\int \sin 4xdx$

$=\frac{1}{2}\times \frac{-\cos 4x}{4}+C$

$I=-\frac{\cos 4x}{8}+C$