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$(1 + i)^{- 3}$

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Solution

$\Rightarrow \frac{1}{(1 + i)^{3}} = \frac{1}{1 + i^{3} + 3 i^{2} + 3 i}$
$= \frac{1}{1 - i - 3 + 3 i}$
$= \frac{1}{- 2 + 2 i} = \frac{1}{(2 - 2 i)}$
$- (2 + 2 i)$

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