Question

Solve :
${(-2-\frac{1}{3}i)}^3$

Answer 1

$=-1{\left(2+\frac{i}{3}\right)}^3$

$=-1\left(8+4i+\frac{2i^2}{3}+\frac{i^3}{9}\right)$

$=-1\left(8-\frac{2}{3}+4i+\frac{-i}{9}\right)$

$=-1\left(\frac{22}{3}+\frac{33i}{9}\right)$

On solving we get,

$=\frac{-22}{3}-\frac{35i}{9}$