Solve: |2x−5|<1
Let 2x−5=y
Given, |y|<1=>|y|−1<0Now, when y>0 , we have |y|=ySo, y−1<0 =>y<1
=>2x−5<1
=>x<62=3 -- (1)
And when y<0 , we have |y|=−y
So, −y−1<0
y>−1
=>2x−5>−1
=>x>2 -- (2) From (1),(2);x∈(2,3)