Solve : $(3 x - \frac{1}{2 y}) (3 x + \frac{1}{2 y})$

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Solution

$(3 x - \frac{1}{2 y}) (3 x + \frac{1}{2 y})$
As $(a - b) (a + b) = a^{2} - b^{2}$
$= ((3 x)^{2} - (\frac{1}{2 y})^{2})$
$= 9 x^{2} - \frac{1}{4 y^{2}}$

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