Question

Solve
$(\frac{-5}{4}+\frac{3}{8})+\frac{-7}{6}$

Answer 1

$(\frac{-5}{4}+\frac{3}{8})+\frac{-7}{6}$

$=(\frac{-5\times 2}{4\times 2}+\frac{3}{8})+\frac{-7}{6}$

$=\left(\frac{-10+3}{8}\right)+\frac{-7}{6}$

$=\frac{-7}{8}+\frac{-7}{6}=-7(\frac{1}{8}+\frac{1}{6})$

$=-7(\frac{1\times 3}{8\times 3}+\frac{1\times 4}{6\times 4})$

$=-7\times \frac{7}{24}=\frac{-49}{24}$