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Complex Numbers

Solve 12-2+1...

Question

Solve
${(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}$

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Solution

$(\frac{1}{2})^{- 2} + (\frac{1}{3})^{- 2} + (\frac{1}{4})^{- 2}$
$= (\frac{2}{1})^{2} + (\frac{3}{1})^{2} + (\frac{4}{1})^{2} = 2^{2} + 3^{2} + 4^{2}$
=4+9+16=29.

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