Solve:
$(a^{2} + b^{2} +2ab) - (a^{2} + b^{2} - 2ab)$

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Solution

solution: -
$(a^{2} + b^{2} + 2 a b) - (a^{2} + b^{2} - 2 a b)$

$= a^{2} + b^{2} + 2 a b - a^{2} - b^{2} + 2 a b$

$= 4 a b$

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Similar questions

Q. Evaluate:

\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. Simplify:
(a² + b² + 2ab) − (a² + b² −2ab)

Find:
$(a + b + c) \times (a + b - c) =$

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Solve:(a2 + b2+2ab) - (a2 + b2 - 2ab)

solution: -(a2+b2+2ab)−(a2+b2−2ab)=a2+b2+2ab−a2−b2+2ab=4ab

Solve:
$(a^{2} + b^{2} +2ab) - (a^{2} + b^{2} - 2ab)$

solution: -
$(a^{2} + b^{2} + 2 a b) - (a^{2} + b^{2} - 2 a b)$

$= a^{2} + b^{2} + 2 a b - a^{2} - b^{2} + 2 a b$

$= 4 a b$