Solve : $l o g_{9} 27 - l o g_{2} 79$

Open in App

Solution

Given, $l o g_{9} 27 - l o g_{27} 9$

$= l o g_{3^{2}} 3^{3} - l o g_{3^{3}} 3^{2}$

$= \frac{3}{2} l o g_{3} 3 - \frac{2}{3} l o g_{3} 3$

$= \frac{3}{2} - \frac{2}{3} = \frac{5}{6}$

Suggest Corrections

Similar questions

{log}_{9} 27 - {log}_{27} 9

{log}_{9} 27 - {log}_{27} 9

l o g_{9} 27 - l o g_{27} 9

{log}_{9} 27 - {log}_{27} 9 = k

36 k

x

{log}_{6} 9 - {log}_{9} 27 + {log}_{8} x = {log}_{64} x - {log}_{6} 4

Join BYJU'S Learning Program