Solve problem- 2x - 3 - x-1 - 6 - 7x-1 - 4 -2 1 - 6

2x3 x 16+7x 14=136 16x 4x+42x 624=136 54x=54 x=1 ...

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Fundamental Theorem of Arithmetic

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Solve problem:
$\frac{2 x}{3} - \frac{x - 1}{6} + \frac{7 x - 1}{4} = 2 \frac{1}{6}$

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Solve : $\frac{2 x}{3} - \frac{x - 1}{6} + \frac{7 x - 1}{4} = 2 \frac{1}{6} .$

Hence, find the value of 'a', if $\frac{1}{a} + 5 x = 8.$

x

\frac{1 - x}{6} + \frac{2 x}{3} - \frac{1 - \frac{3}{7 x}}{4} = 2 \frac{1}{6}

\frac{7 x - 1}{4} - \frac{1}{3} (2 x - \frac{1 - x}{2}) = 6 \frac{1}{3}

\frac{2 x}{3} - \frac{x - 1}{6} + \frac{7 x - 1}{4} = 2 \frac{1}{6}

x

a

\frac{1}{a} + 5 x = 8.

2 x + 6 - 7 x + 21 - 8 x - 88 = 3 x - 3 (7 x + 2)

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