∫ 1dx = ∫(2 + 1v + 2)dv ∫ 1 dx = ∫ 2 dv + ∫1v + 2 dv x = 2v + log (v + 2) + c Hence, this is the answer ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration by Parts

Solve ⇒∫ dx=...

Question

Solve
$\Rightarrow \int d x = \int (2 + \frac{1}{v + 2}) d v$

Open in App

Solution

$\int 1 d x = \int (2 + \frac{1}{v + 2}) d v$
$\int 1 d x = \int 2 d v + \int \frac{1}{v + 2} d v$
$x = 2 v + log (v + 2) + c$
Hence, this is the answer

Suggest Corrections

Similar questions

\int \frac{2 v^{2}}{v^{2} + v - 2} d v

v

u

d

d x = \frac{x d v}{v^{2} - a^{2}}

\frac{1}{2} \int \frac{1}{2} [x] d x

\int \frac{u}{v} d x

Join BYJU'S Learning Program