∫ 1dx = ∫(2 + 1v + 2)dv ∫ 1 dx = ∫ 2 dv + ∫1v + 2 dv x = 2v + log (v + 2) + c Hence, this is the answer ...

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Integration by Parts

Solve ⇒∫ dx=...

Question

Solve
$\Rightarrow \int d x = \int (2 + \frac{1}{v + 2}) d v$

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Solution

$\int 1 d x = \int (2 + \frac{1}{v + 2}) d v$
$\int 1 d x = \int 2 d v + \int \frac{1}{v + 2} d v$
$x = 2 v + log (v + 2) + c$
Hence, this is the answer

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