Solve: ${sin}^{2} x - sin x - 2 = 0$

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Solution

${sin}^{2} x - sin x - 2 = 0 {sin}^{2} x - 2 sin x + sin x - 2 = 0 sin x (sin x - 2) - 1 (sin x - 2) = 0 (sin x - 1) (sin x - 2) = 0 sin x = 1 ⟹ x = \frac{π}{2}$
$sin x$ cannot be $2$

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