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Trigonometric Ratios of Multiples of an Angle

Solve : sin ...

Question

Solve :
$sin (A - B) = \frac{sin A}{X} - \frac{cos A}{Y}$

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Solution

$S i n (A - B) = S i n A cos B - cos A sin B$
$X = s e c A Y = c o s e c B$
Hence,
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