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Question

Solve:sin(2cos1(35))

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Solution

sin(2cos1(35))
Let cos1(35)=α; α[0,π]
cos(α)=35
α[0,π] and cosα<0
α is in II quadrant.
sin(α)>0
sin(α)=1cos2(α)=1925
sin(α)=(1625)12
sin(2cos1(3/5))=sin(2α)
=2sin(α)cos(α)
=245(35)
=2425.

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