Solve: $tan 20^{o} + tan 40^{o} + t a n 60^{o} + . . . tan 180^{o} =$

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
$t a n 20 + t a n 40^{\circ} + t a n 60^{\circ} + . . .$
$+ t a n 140^{\circ} + t a n 160 + t a n 180^{\circ}$
$= t a n 20^{\circ} + t a n (180 - 20)^{\circ}$
$+ t a n 40^{\circ} + t a n (180 - 40^{\circ})$
$+ t a n 60^{\circ} + t a n (180 - 60^{\circ})$
$+ t a n 80^{\circ} + t a n (180 - 80^{\circ})$
$+ t a n 180^{\circ}$
$= t a n 180^{\circ} = 0$
$[∵ t a n (180 - θ) = - t a n θ]$

Suggest Corrections