Solve- tan55o-A-35o-A

tan( 55 A ) ( 35 + A ) = tan( 55 A ) tan( 90 ( 35 + A ) ) ( ∵tan( 90 θ) = θ) = tan( 55 A ) tan( 90 35 A ) = tan( 55 A ...

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Circular Measurement of Angle

Solve: tan55...

Question

Solve:
$tan (55^{o} - A) - cot (35^{o} + A)$

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Solution

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csc (65^{o} + 0) - sec (25^{o} - 0) - t a n (55^{o} + 0) + cot (35^{o} - 0)

\frac{sec θ cos e c (90^{o} - θ) - tan θ cot (90^{o} - θ) + ({sin}^{2} 35^{o} + {sin}^{2} 55^{o})}{tan 10^{o} tan 20^{o} tan 45^{o} tan 70^{o} tan 80^{o}}

tan 55^{o} = \frac{cos 10^{o} + sin 10^{o}}{cos 10^{o} - sin 10^{o}}

A B C D

∠ B C A = 35^{o}

∠ A D C

M A = 5 c m, ∠ A = 110^{o}, ∠ R M A = 35^{o}

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