The given equation is,
21 x 2 −28x+10=0
Comparing the given equation with a x 2 +bx+c=0 , we get
a=21 b=−28 c=10
D= b 2 −4ac = ( −28 ) 2 −4×21×10 =−56
The required solutions are,
x= −b± D 2a = −( −28 )± −56 2×21 = 28± 56 i 42 = 28 42 ± 2 14 i 42 = 2 3 ± 14 21 i
Therefore, the solutions to the equation are 2 3 ± 14 21 i .
Solve 21x2−28x+10=0
Solve the following quadratics 21x2−28x+10=0