wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the equation: 3(k+1)=24 using the method of transposition.


A
k=6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
k=7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

k=7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
k=6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

k=7


3(k+1)=24

Transpose 3 to the RHS:

k+1=243=> k+1=8

Transpose 1 to the RHS
K=81=> k=7


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon