Question

Solve the equation by using formula: $x^2-4x+2=0$.

Answer 1

Given: $x^2-4x+2=0$

Formula to find the value of $x$ is given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$, where the standard form of the equation is $a{x}^2+bx+c$

Here, $a=1,b=-4,c=2$

$\therefore$ $x=\frac{-(-4)\pm \sqrt{(-4{)}^2-4\times 1\times 2}}{2\times 1}$

$\therefore$ $x=\frac{4\pm \sqrt{16-8}}{2}$

$\therefore$ $x=\frac{4\pm \sqrt{8}}{2}$

$\therefore$ $x=\frac{4\pm 2\sqrt{2}}{2}$

$\therefore$ $x=\frac{2(2\pm \sqrt{2})}{2}$

$\therefore$ $x=2\pm \sqrt{2}$

$\therefore$ $x=2+\sqrt{2}$ and $x=2-\sqrt{2}$