Solve the equation for x , y , z and t if

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Solution

The given equation is,

2[ x z y t ]+3[ 1 −1 0 2 ]=3[ 3 5 4 6 ]

Simplify the above equation.

2[ x z y t ]+3[ 1 −1 0 2 ]=3[ 3 5 4 6 ] [ 2x 2z 2y 2t ]+[ 3 −3 0 6 ]=[ 9 15 12 18 ] [ 2x+3 2z−3 2y 2t+6 ]=[ 9 15 12 18 ]

Now, compare both sides of the above equation.

2x+3=9 2x=6 x=3

And

2y=12 y=6

Again,

2z−3=15 2z=18 z=9

And

2t+6=18 2t=12 t=6

Thus, the value of xis 3, the value of yis 6, the value of zis 9and the value of tis 6.

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