Solve $1 - (x - 2) - [(x - 3) - (x - 1)] = 0$

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Solution

Solving given equation, we get
$1 - (x - 2) - [(x - 3) - (x - 1)] = 0 \Rightarrow 1 - x + 2 - [x - 3 - x + 1] = 0 \Rightarrow 3 - x - [- 2] = 0 \Rightarrow 3 - x + 2 = 0 \Rightarrow 5 - x = 0 \Rightarrow x = 5$
Hence, the solution of the given equation is $x = 5 .$

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