The correct option is D (−1,2)
−x+2y=5 .....(1)
2x+2y=2 .....(2)
Multiply equation (2) by 4 and then subtract the equation (3) and (4)
−2x+4y=10 ....(3)
2x+2y=2 .....(4)
_____________
6y=12
⇒y=126=2
Put the value of x in equation (1), we get
−x+2(2)=5
⇒−x+4=5
⇒x=4−5
⇒x=−1
Therefore the solution is (−1,2).