Solve the following
(a) $p + 4 = 15$
(b) $m - 9 = 4$
(c) $x + 2 x + 1 = 4 x + 6$
(d) $9 a - 3 a - 4 a - 6 = 0$

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Solution

(a) $p + 4 = 15$
$\Rightarrow p = 15 - 4$
$\Rightarrow p = 11$
(b) $m - 9 = 4$
$\Rightarrow m = 9 + 4$
$\Rightarrow m = 13$
(c) $x + 2 x + 1 = 4 x + 6$
$\Rightarrow 3 x + 1 = 4 x + 6$
$\Rightarrow 4 x - 3 x = 1 - 6$
$\Rightarrow x = - 5$

(d) $9 a - 3 a - 4 a - 6 = 0$
$\Rightarrow 6 a - 4 a = 6$
$\Rightarrow 2 a = 6$
$\Rightarrow a = 3$

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The factors of 12ab + 9a + 12 + 16b are

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