Question

Solve the following algebraic expressions by both trial and error method and balancing equation.
$3-x=2$

Answer 1

Given $3-x=2$

Let $x=1,LHS=3-1=2,RHS=2$

As $LHS=RHS$

By trial and error method

So $x=1$

By balancing equation

$3-x=2⟹x=3-2=1$