Question

Solve the following algebraic expressions by both trial and error method and balancing equation.
$y+10=25$

Answer 1

Given $y+10=25$

Let $y=1,LHS=1+10=11,RHS=25$

$LHS\ne RHS$

Let $y=15,LHS=15+10=25,RHS=25$

As $LHS=RHS$

By trial and error method

So $y=15$

By balancing equation

$y+10=25⟹y=25-10=15$