Solve the following differential equation- x d y d x - 2 y - x 2 log x

x dy dx +2y= x ^ 2 log x dy dx + 2 x (y)=xlog x dy dx +Py=Q I.F= e ^∫ Pdx #160; = e ^∫ 2 x dx #160; = e ^ 2log x = x ^ 2 ...

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Solving Linear Differential Equations of First Order

Solve the fol...

Question

Solve the following differential equation:
$x \frac{d y}{d x} + 2 y = x^{2} log x$

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Solution

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x \frac{d y}{d x} + 2 y = x^{2} log x

x \frac{d y}{d x} + 2 y = x^{2} log x

x \frac{d y}{d x} + 2 y = x^{2} l o g x .

For the given differential equation find the general solution.

$x \frac{d y}{d x} + 2 y = x^{2} l o g x$

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