Question

Solve the following:

$\frac{2x-3}{4}+8\ge 2+\frac{4x}{3}$

• A. $x\le 6.3$
• B. $x\le 7$
• C. $x\le 7.3$
• D. $x\le 8.3$

Answer 1

The correct option is A $x\le 6.3$

$\frac{2x-3}{4}+8\ge 2+\frac{4x}{3}\Rightarrow \frac{x}{2}-\frac{3}{4}+6-\frac{4x}{3}\ge 0$

$\Rightarrow \frac{5x}{6}\le \frac{21}{4}\Rightarrow x\le 6.3$