Question

Solve the following equation:
$2x^2-13x+15=0$

Answer 1

Given equation is
$2x^2-13x+15=0$
Here $a=2,b=-13,c=15$
Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
$x=\frac{-(-13)\pm \sqrt{{(-13)}^2-4\times 2\times 15}}{2\times 2}$
$\Rightarrow x=\frac{13\pm \sqrt{169-120}}{4}$
$\Rightarrow x=\frac{13\pm \sqrt{49}}{4}$
$\Rightarrow x=\frac{13\pm 7}{4}$
Taking $+$ ve sign
$x=\frac{13+7}{4}=\frac{20}{4}=5$
Taking $-$ ve sign
$x=\frac{13-7}{4}=\frac{6}{4}=\frac{3}{2}$
Hence, the required solutions are $x=5,\frac{3}{2}$