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Question

Solve the following equation:

28=4+3(t+5)


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Solution

Step:Solving the equation.

Given :- 28=4+3(t+5)

28=4+3t+15 (Expanding the bracket on R.H.S. )

28=19+3t

-3t=19-28 (Transporting 28 to R.H.S. and 3t on L.H.S.)

-3t=-9

-3t-3=-9-3 (Dividing both side of equation by -5)

t=3

Therefore, t=3 is the required solution


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