Question

Solve the following equation:$\frac{7y+4}{y+2}=\frac{-4}{3}$

Answer 1

Cross multiply the terms and then solve for $y$ by applying mathematical operations.

Therefore,

$\begin{array}{c}\frac{7y+4}{y+2}=\frac{-4}{3}\\ 7y\left(3\right)+4\left(3\right)=y(-4)+2(-4)\\ 21y+12=-y-8\end{array}$

Take the common terms on one side.

$\begin{array}{c}21y+y=-8-12\\ 22y=-20\\ y=\frac{-20}{22}\\ y=\frac{-4}{5}\end{array}$

Hence, the value of $y$in $\frac{7y+4}{y+2}=\frac{-4}{3}$is $\frac{-4}{5}$.