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Byju's Answer
Standard VIII
Mathematics
Solving Linear Equations Using Transpose of Terms
Solve the fol...
Question
Solve the following equation and check your results:
2
x
−
1
=
14
−
x
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Solution
Given equation is
2
x
−
1
=
14
−
x
.
Transposing
−
1
to RHS and
−
x
to LHS, we get:
2
x
+
x
=
14
+
1
3
x
=
15
Now, on dividing both sides by
3
, we get:
We will get,
x
=
5
Hence,
x
=
5
is the solution of
2
x
−
1
=
14
−
x
.
Let's check the solution by substituting it into the equation:
LHS
⇒
2
x
−
1
=
2
×
5
−
1
=
10
−
1
=
9
RHS
⇒
14
−
x
=
14
−
5
=
9
Here, LHS
=
RHS
So, the solution is correct.
Hence,
x
=
5
is the solution of
2
x
−
1
=
14
−
x
and is verified.
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