Question

Solve the following equation and check your results: $4z+3=6+2z$

Answer 1

Step 1: Solve the given equation by Rearranging and combining the like terms.

$\begin{array}{l}4z+3=6+2z\\ \Rightarrow 4z-2z=6-3\\ \Rightarrow 2z=3\\ \Rightarrow z=\frac{3}{2}\end{array}$

Step 2: Verify the result by substituting $z=\frac{3}{2}$in the given equation.

$\begin{array}{l}4\times \frac{3}{2}+3=6+2\times \frac{3}{2}\\ \Rightarrow 6+3=6+3\\ \Rightarrow 9=9\\ \Rightarrow \mathrm{LHS}=\mathrm{RHS}\end{array}$

Hence the solution of $4z+3=6+2z$ is $z=\frac{3}{2}$and it is verified.