Solve the following equation by factorisation:
√3 x 2+10x+7√3=0
√3x^2 + 10x + 7√3 = 0
√3x^2 + 7x + 3x + 7√3 = 0
x ( √3x + 7 ) + √3 ( √3x + 7 ) = 0
(x + √3) ( √3x + 7) = 0
x + √3 = 0 , √3x +7 = 0
x= -√3 x= -7/ √3
So, the 2 zeroes are -√3 and -7/√3
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