√log2x−0.5=log2√x⇒2√log2x−1=log2x⇒(√log2x)2−2√log2x+1=0⇒√log2x=1⇒log2x=1⇒x=2.
√log2x−0.5=log2√x, then x equals
Solve for x in the equation log[log(2+log2(x+1))]=0