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Addition and Subtraction of Algebraic Expression

Solve the fol...

Question

Solve the following equation:
$\sqrt{x^{2} + 8} = 2 x + 1$

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Solution

$\sqrt{x^{2} + 8} = 2 x + 1 x^{2} + 8 = {(2 x + 1)}^{2} x^{2} + 8 = 4 x^{2} + 4 x + 1 3 x^{2} + 4 x - 7 = 0 {3 x}^{2} + 7 x - 3 x - 7 = 0 (3 x + 7) (x - 1) = 0 x = \frac{- 7}{3}, 1$

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