Question

Solve the following equation for x :

$4^{2x}=\frac{1}{32}$

Answer 1

$4^{2x}=\frac{1}{32}$

$(2^2{)}^{2x}=\frac{1}{2^5}$

$2^{4x}=2^{-5}$

As the bases are same, equating the powers

$4x=-5$

$x=-\frac{5}{4}$