Question

Solve the following equation using the general formula:
$x^2+10x+6=0$

Answer 1

$x^2+10x+6=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-10\pm \sqrt{{10}^2-4\times 6\times 1}}{2}=\frac{-10\pm \sqrt{76}}{2}$

$x=-5\pm \sqrt{19}$

$\Rightarrow x=-5-\sqrt{19}$,

$-5+\sqrt{19}$.