Question

Solve the following equations.

(15) $\frac{3y+5}{3-7y}=\frac{5}{3}$

Answer 1

$\frac{3y+5}{3-7y}=\frac{5}{3}$
⇒ 3(3y+5) = 5(3 − 7y)
⇒ 9y + 15 =15 − 35y
⇒ 44y = 0
∴ y = 0